一道定积分简单计算题 详细过程谢谢
(1) ∫0到5 4x dx （2）∫0到5 (x^2-2x)dx (3)1到2（根号下x-1）dx （4）-1到3 （3x^2-2x+1）dx ∫(0,5)4xdx =2x²|(0,5) =50-0 =50 ∫(0,5)(x²-2x)dx =(1/3x³-x²)|(0,5) =(125/3-25)-(0-0) =50/3 ∫(1,2)√x-1dx =2/3(x-1)^(3/2)|(1,2) =2/3(2-1)^(3/2)-2/3(1-1)^3/2 =2/3 ∫(-1...