并联电路的分流公式怎样推导出来的
设R1、R2并联,流过的电流分别为I1、I2,总电流为I。
并联电阻为R并=(R1R2)/(R1+R2) I1R1=I2R2=IR并 I1=IR并/R1 =I[(R1R2)/(R1+R2)]/R1 =IR2/(R1+R2) I2=IR并/R2 =I[(R1R2)/(R1+R2)]/R2 =IR1/(R1+R2)。
设R1、R2并联,流过的电流分别为I1、I2,总电流为I。
并联电阻为R并=(R1R2)/(R1+R2) I1R1=I2R2=IR并 I1=IR并/R1 =I[(R1R2)/(R1+R2)]/R1 =IR2/(R1+R2) I2=IR并/R2 =I[(R1R2)/(R1+R2)]/R2 =IR1/(R1+R2)。